Dinuclear versus mononuclear zinc compounds from reduction of LZnCl 2 (L = α-diimine ligands): Effects of the ligand substituent, reducing agent, and solvent

Jie Yu, Xiao Juan Yang*, Yanyan Liu, Zhifeng Pu, Qian Shu Li, Yaoming Xie, Henry F. Schaefer, Biao Wu

*Corresponding author for this work

Research output: Contribution to journalArticlepeer-review

61 Citations (Scopus)

Abstract

A Zn-Zn-bonded compound, [K(THF)2]2[(L iPr)Zn-Zn(Lipr)] (2) and three mononuclear zinc compounds, [Zn(LMe)2Na2(Et2O)2] (3), [Zn(LEt,)2Na2(THF)2] (4), and [Zn(LEt)2K2]., (5), with N-aryl substituted a-diimine ligands LiPr, LMe, and LEt (L = [(2,6-R2C6H3)N(Me)C]2, R = iPr, Me, Et, respectively) have been synthesized from the reduction of the LZnCl2 precursors by the alkali metal Na or K. X-ray structural analyses show that the compounds have a [Zn2L 2]2- (2) or [ZnL2]2- (3-5) core incorporating Na+ or K+ ions solvated by THF or Et 2O molecules, except for 5, which displays a 2D polymeric structure formed by intermolecular K-C bonds due to the lack of K - solvent interactions. In compound 2, the formal Zn2+ ion in the precursor is reduced to Zn+, while in 3-5 it remains unreduced. The neutral ligands in the precursor, however, are doubly reduced to a dianion, L2-, in all compounds, as evidenced by the bond lengths of the N-C=C-N moiety of the ligands. Effects of the ligand substituent, reducing agent, and solvent on the products have been studied, which reveal that the steric bulk of the ligand is the most important factor that determines whether the Zn-Zn bond can be formed. DFT computations show that the Zn-Zn bond in 2 is formed mainly by the 4s orbitais of zinc. The results of natural charge and orbital analyses also confirm the reduction of the ligands to their dianionic forms.

Original languageEnglish
Pages (from-to)5800-5805
Number of pages6
JournalOrganometallics
Volume27
Issue number22
DOIs
Publication statusPublished - 24 Nov 2008
Externally publishedYes

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