Abstract
An edge of G is singular if it does not lie on any triangle of G; otherwise, it is non-singular. A vertex u of a graph G is called locally connected if the induced subgraph G[N(u)] by its neighborhood is connected; otherwise, it is called locally disconnected. In this paper, we prove that if a connected claw-free graph G of order at least three satisfies the following two conditions: For each locally disconnected vertex v of G with degree at least 3, there is a nonnegative integer s such that v lies on an induced cycle of length at least 4 with at most s non-singular edges and with at least s-3 locally connected vertices; for each locally disconnected vertex v of G with degree 2, there is a nonnegative integer s such that v lies on an induced cycle C with at most s non-singular edges and with at least s-2 locally connected vertices and such that the subgraph induced by those vertices of C that have degree two in G is a path or a cycle, then G is Hamiltonian, and it is best possible in some sense. Our result is a common extension of two known results in Bielak (2000) and in Li (2002); hence also of the results in Oberly and Sumner (1979) and in Ryjáček (1990).
| Original language | English |
|---|---|
| Pages (from-to) | 2042-2050 |
| Number of pages | 9 |
| Journal | Discrete Mathematics |
| Volume | 338 |
| Issue number | 11 |
| DOIs | |
| Publication status | Published - 6 Jun 2015 |
Keywords
- Claw-free graph
- Closure
- Hamiltonian
- Locally disconnected vertex
- Singular edge
Fingerprint
Dive into the research topics of 'Hamiltonian claw-free graphs with locally disconnected vertices'. Together they form a unique fingerprint.Cite this
- APA
- Author
- BIBTEX
- Harvard
- Standard
- RIS
- Vancouver